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3.5-1/2x=0.5^x-3
We move all terms to the left:
3.5-1/2x-(0.5^x-3)=0
Domain of the equation: 2x!=0We get rid of parentheses
x!=0/2
x!=0
x∈R
-1/2x-0.5^x+3+3.5=0
We multiply all the terms by the denominator
-(0.5^x)*2x+3*2x+(3.5)*2x-1=0
We multiply parentheses
-0x^2+3*2x+7x-1=0
Wy multiply elements
-0x^2+6x+7x-1=0
We add all the numbers together, and all the variables
-1x^2+13x-1=0
a = -1; b = 13; c = -1;
Δ = b2-4ac
Δ = 132-4·(-1)·(-1)
Δ = 165
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-\sqrt{165}}{2*-1}=\frac{-13-\sqrt{165}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+\sqrt{165}}{2*-1}=\frac{-13+\sqrt{165}}{-2} $
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